Question 3 (a)

Spearman's rank correlation of performance and customer satisfaction, with tied ranks

9 marks

Time to write
About 18 minutes
Topic
Correlation

Question

Question 3 (a) · 9 marks

A company that installs water purifiers is studying how employee performance relates to customer satisfaction in its sales department. The performance scores and the consumer satisfaction scores of 10 sales representatives are shown below:

Sales RepresentativesPerformance ScoresCustomer Satisfaction Scores
A4744
B5249
C4340
D4447
E4043
F4946
G4240
H3336
I3739
J4442

Determine, using Spearman's Rank Correlation Coefficient, whether there is a significant correlation between the employees' performance scores and the customer satisfaction scores. Interpret the result.

Reworded from the university paper; the task is the same. The original paper belongs to the University of Delhi. See DU's question bank.

Before you write

Read off the question and its marks

18 minfor 9 marks

Read from the question

  • Determine…Interpret…Two asks in one question: answer both.

Write it in this order

  1. Read; underline the asks; jot your points 1 min
  2. 1 Ranking, including tied ranks 3 marks 5 min
  3. 2 ΣD² and the tie correction 2 marks 4 min
  4. 3 Rank correlation coefficient 2 marks 4 min
  5. 4 Significance and interpretation 2 marks 3 min
  6. Check: every ask answered, key terms underlined 1 min

Short on time? Trim steps 1–4 evenly rather than skip one: each is capped at its own marks.

Try it first. About 18 minutes for 9 marks. Write it out, then open the solution.

Solution

Hover or tap a marked figure, like 72,000, to see how it is made and where else it appears.

Ranking. Rank 1 is given to the highest score in each series. Where scores are equal, each receives the average of the ranks they would occupy: performance 44 (D and J) share ranks 4 and 5, so each gets 4.5; satisfaction 40 (C and G) share ranks 7 and 8, so each gets 7.5. With tied ranks, Spearman's formula adds a correction of (m³ − m) / 12 to ΣD² for every group of m tied values:

ρ = 1 − 6[ΣD² + Σ(m³ − m)/12] / [n(n² − 1)], with D the difference in ranks.

Working table

RepresentativePerformanceSatisfactionRank R₁Rank R₂D = R₁ − R₂D²
A474434−11
B52491100
C434067.5−1.52.25
D44474.522.56.25
E40438539
F494623−11
G424077.5−0.50.25
H3336101000
I37399900
J44424.56−1.52.25
Total022

Rank correlation coefficient

Two ties of m = 2 (one in each series): correction = (2³ − 2)/12 + (2³ − 2)/12 = 0.5 + 0.5 = 1.

ρ = 1 − 6(22 + 1) / [10(10² − 1)] = 1 − 138 / 990 = 1 − 0.1394 = 0.8606.

Is the correlation significant? Judged by its probable error (Unit 3 of the syllabus,): P.E. = 0.6745 (1 − ρ²) / √n = 0.6745 × (1 − 0.7406) / √10 = 0.0553, and 6 × P.E. = 0.3319. Since ρ = 0.8606 is far larger than 6 × P.E., the correlation is significant: it is not a chance result of these ten representatives.

Interpretation. There is a high positive rank correlation (0.86) between the representatives' performance scores and the satisfaction of their customers: representatives who perform better generally leave customers more satisfied. The company can use performance reviews and training as a lever on customer satisfaction, keeping in mind that correlation alone does not prove which one causes the other.

Where the 9 marks sit

#ComponentMarks
1Ranking, including tied ranks3
2ΣD² and the tie correction2
3Rank correlation coefficient2
4Significance and interpretation2
Total9
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